A and B are friends. They decide to meet between 1 PM and 2 PM on a given day. There is a condition that whoever arrives first will not wait for the other for more than 15 minutes. The probability that they will meet on that day is- (A) 1/4 (B) 1/16 (C) 7/16 (D) 9/16

Answers (1)

Solution: Let A arrives first B comes second 

probability for B to come within 15 minutes =15/60=1/4

Let B arrives first A come second

Prabability Of A come within 15 minutes =15/60=1/4

Out of these two case s 

only one is possible Either A or B come first 

so  Prabability for A come first =1/2 

prabability of B come first =1/2

 \ 1/2	imes 1/4+1/2	imes 1/4=1/4

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