A beam of light converges at a point P. Now a convex lens is placed in the path of the convergent beam at 15 cm from P. At what point does a beam converge if the convex lens has a focal length 10 cm?

 

 

 
 
 
 
 

Answers (1)
S safeer

\frac{1}{v}-\frac{1}{u}=\frac{1}{f}    (lens formula)

v = image distance

u = object distance

f = focal length

here, u=+15\: cm

         f=10\: cm

\frac{1}{v}=\frac{1}{f}+\frac{1}{u}

\frac{1}{v}=\frac{1}{10}+\frac{1}{15}

\frac{1}{v}=\frac{5}{30}

v=6\; cm

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