so using
where
g= acceleration due to gravity
s= total height
and v=0
then we get
for earth
So using
we get
h=12 m
so the boy can jump height of 12 m on moon's surface
g on moon = 1/6 th (g on earth)
6g (moon) = g (earth)
Since, Distance of jump with g on earth = 2m
Therefore, Distance of jump with g on moon =6 × 2 = 12m
Hence, he will jump 12m on moon .
Given,
Se=2m
ge=10m/s²
gm=1/6of ge
sm=?
Se=1/6ge
Se=sm/6
for se we have =2m
so,
2m=sm/6
sm=2X6
hence boy jump 12 m on moon