A bucket contains 8 kg of water at 25°C and 2 kg of water at 80°C is poured into it. Neglecting the heat absorbed by the bucket, calculate the final temperature of water.

Answers (1)

Specific heat capacity of water=c=4200 J/kgK

Let the final temperature of water=T

with the help of The principle of calorimetry

We can write

m_1 *c *(T_1-T) = m_2 * c *(T-T_2)\\\Rightarrow 2*c(80-T)=8*c*(T-25)\\\Rightarrow 160-2T = 8T-200\\\Rightarrow 360 = 10T\\\Rightarrow T=36^0

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