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  • A concave lens of focal length is used to form an image of an object of length <img alt="9\; cm" src="https://entrancecorner.codecogs.com/gif.latex?%5Ci

A concave lens of focal length 60\; cm is used to form an image of an object of length 9\; cm kept at a distance of 30\; cm from it. Use lens formula to determine the nature, position and length of the image formed. Also draw labelled ray diagram to show the image formation in the above case.

 

 

 

 
 
 
 
 

Answers (1)

Concave lens-

focal length (f)=-60\; cm

Object length (h)=9\; cm

Object distance (u)=-30\; cm

Lens formula, \frac{1}{v}-\frac{1}{u}=\frac{1}{f}

                        \frac{1}{v}=\frac{1}{f}+\frac{1}{u}

                         v=\frac{-1}{60}+\left ( \frac{-1}{30} \right )

    m=\frac{v}{u}=\frac{-20}{-30}=\frac{2}{3}

m=\frac{{h}'}{h}\Rightarrow {h}'=m\times h

                        {h}'=\frac{2}{3}\times 9

                        {h}'=6\; cm

Image is virtual, erect and smaller than object.

   

 

 

 

 

Posted by

Sumit Saini

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