Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • A converging beam of light travelling in air converges at a point  as shown in the figure. When a glass sphere of refractive index 1·5 is introduced in between the path of

A converging beam of light travelling in air converges at a point P as shown in the figure. When a glass sphere of refractive index 1·5 is introduced in between the path of the beam, calculate the new position of the image. Also, draw the ray diagram for the image formed.

            

 

 

 

 
 
 
 
 

Answers (1)

For the first refraction, we have u=20cm and R=5cm,     n_{2}=1.5, n_{1}=1 

 \frac{n_{2}}{v}-\frac{n_{1}}{u}=\frac{n_{2}-n_{1}}{R}

\frac{1.5}{v}-\frac{1}{20}=\frac{(1.5-1)}{5}         

\frac{3}{2v}=\frac{1}{10}+\frac{1}{20}=\frac{3}{20}

v=10cm

For the 2nd refraction

u=0 

then,

\frac{1}{v}-\frac{1.5}{0}=\frac{1-1.5}{-5}

v=0

So, the final image will be a pole of the surface 2.

Posted by

Safeer PP

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Board exams twice a year from 2025, no plan for semesters: MoE
anam-khan

CBSE Class 12 board exams 2025 to have 50% competency-based questions; no change in 10th
anam-khan

CBSE Class 12 board exams 2024 over; expected result date, trends of last 10 years

Latest Question