A Convex lens of focal lenth 10 cm is placed at a distance of 12 cm from a wall,Calculate the distance from the lens where an object be placed so as to form its distinct real images on the wall. plz solve .............

Answers (1)

Here, the real image is formed on the wall which is at a distance of 12 cm from the convex lens. This means that the distance of image from the convex lens or image distance will be 12 cm. Since a real image is fomred on the right side of the lens, so this image distance will be positive.
Now, Image distance, v=±12v (A real image)
Object distance, u=? (To be calculated)
Focal length, f=+10 cm (it is convex lens)
Putting these values in the lens formula:
\\ \frac{1}{v}-\frac{1}{u}=\frac{1}{f}$ \\ \\ We get: $\frac{1}{12}-\frac{1}{u}=\frac{1}{10}$ \\ \\ $\frac{1}{12}-\frac{1}{10}=\frac{1}{u}$ \\ \\ $\frac{5-6}{60}=\frac{1}{u}$ \\ \\ $-\frac{1}{60}=\frac{1}{u}$ \\ \\ So, Object distance, u=-60 cm

Thus, the obect should be place at a distance of 60 cm in front of the convex lens. The minus sign shows that the obect is on the left side of the lens.

Preparation Products

JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
Buy Now
Rank Booster NEET 2021

This course will help student to be better prepared and study in the right direction for NEET..

₹ 13999/- ₹ 9999/-
Buy Now
Knockout JEE Main April 2021 (Easy Installments)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 4999/-
Buy Now
Knockout NEET May 2021

An exhaustive E-learning program for the complete preparation of NEET..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout NEET May 2022

An exhaustive E-learning program for the complete preparation of NEET..

₹ 34999/- ₹ 24999/-
Buy Now
Exams
Articles
Questions