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A die is thrown once. Find the probability of getting (i) a composite number, (ii) a prime number.

Answers (1)

Total no. of outcomes = 6

(i) Composite numbers on dice are 4 and 6

$\therefore P(\text{Composite No.}) = \frac{2}{6} = \frac{1}{3}$

(ii) Prime numbers are 2,3 and 5

$\therefore P(\text{Prime No.}) = \frac{3}{6} = \frac{1}{2}$

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