# A discrete random variable X has the following probability distribution : X 0 1 2 3 4 5 P(X) 4C2 3C2 2C2 C2 C 2C (a) Find the value of C.(b) Find the mean of the distribution.(c) Given find the variance of the distribution.

 X 0 1 2 3 4 5 P(X) 4C2 3C2 2C2 C2 C 2C X.P(X) 0 3C2 4C2 3C2 4C 10C

(a)

C = -1/2 (Negative probability is not possible)

Hence the value of .

(b) Mean of the distribution.

(c) Given:

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