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A force is inclined at 60 to the horizontal. If the horizontal component of force is 40 N calculate the vertical component.

Answers (1)

Horizontal component is 

F cos60=40 , cos60=0.5. Therefore

F=40/0.5=80N

vertical component is 

F_v=80sin60=80\times\frac{\sqrt{3}}{2}=40\sqrt{3}N

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Safeer PP

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