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  • A force of F = 70 N is applied on a block of mass M = 10 Kg placed on a horizonatl surface as shown in the figure . What will be the work do

A force of F = 70 N is applied on a block of mass M = 10 Kg placed on a horizontal surface as shown in the figure. What will be the work done by frictional force in t = 2 sec if the block was initially at rest?

Answers (1)

Given:

The mass of the body is m= 10 kg

The force applied on the body F=70N

The coefficient of kinetic friction =0.6

Since the body starts from rest, the initial velocity of the body is zero.

The time at which the work is to be determined is t=2s

The acceleration produced in the body by the applied force is given by Newton's second law of motion as

Posted by

Satyajeet Kumar

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