# A force of F = 70 N is applied on a block of mass M = 10 Kg placed on a horizonatl surface as shown in the figure . What will be the work done by frictional force in t = 2 sec if block was initially at rest The mass of the body is m= 10 kg

The force applied on the body F=70N

The coefficient of kinetic friction =0.6

Since the body starts from rest, the initial velocity of body is zero.

Time at which the work is to be determined is t=2s

The acceleration produced in the body by the applied force is given by Newtons second law of motion as

Frictional force is given as:

The acceleration produced by the frictional force :

Therefore, the total acceleration of the body:

The distance traveled by the body is given by the equation of motion:

Work done by the frictional force,

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