A game consists of tossing a coin 3 times and noting the outcome each time. If getting the same result in all the tosses is a success, find the probability of losing the game.
In this particular question we have to make the cases to find the probability,
The possible outcome when a coin is tossed 3 times =
{HHH,TTT,HHT,HTH,THH,TTH,TTH,HTT}
From the above cases,
Total number of possible cases = 8
possible outcomes of winning =2
So the possible outcomes of losing = 8-2 =6
Hence the required probability = 6/8= 3/4.