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  • A heater coil develops heat of 800 cal/sec .when 20 volts is applied across its ends.what is the resistance of coil?

A heater coil develops heat of 800 cal/sec .when 20 volts is applied across its ends.what is the resistance of coil?

Answers (1)

1 calorie = 4.184 Joule

800 calorie =3347.2 J

Power = 3347.2 watt

P=V2/R

Therefore

R=V2/P=400/3347.2=0.12 ohm

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