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A machine gun fires 20 bullets per second into a target. Each bullet weighs 150 grams and has a speed of 800 m/s.find the force necessary to hold the gun in position

Answers (1)

F=m\frac{dv}{dt}

here the number of bullets coming out is n=20 bullet/sec

the velocity of bullet=800 m/sec

mass of the bullet=150 x 10-3Kg

The force required to hold is 

F=nmdv=20\times150\times10^{-3}\times800=2400N

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Safeer PP

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