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A merchant has 120 litres of oil of one kind, 180 litres of another kind and 240 litres of third kind. He wants to sell the oil by filling the three kinds of oil in tins of equal capacity. What should be the greatest capacity of such a tin?

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We;need;to;find;the;HCF;or;GCD;that;is;Greatest;Common;Divisor\* Rightarrow 120=2	imes 2	imes 2	imes 3	imes 5\* Rightarrow 180=2	imes 2	imes 3	imes 3	imes 5\*Rightarrow 240=2	imes 2	imes 2	imes 2	imes 3	imes 5\* Rightarrow GCD=2	imes 2	imes 3	imes 5=60\*The;greatest;capacity=60;liters\* So;the;merchant;needs;to;fill;60;liters;of;all;types;of;oils\*

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Deependra Verma

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