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A number x is selected at random from the numbers 1,2,3 and 4 .Another number y is selected at random from the numbers 1,4,9 and 16. Find the probability that product of x and y is less than 16 

 

 

 

 
 
 
 
 

Answers (1)

Total ways of selecting two numbers = 

\left \{ \right. (1,1)(1,2) (1,3) ( 1,4)\\\\(4,1)(4,2)(4,3)(4,4)\\\\(9,1)(9,2)(9,3)(9,4)\\\\(16,1)(16,2)(16,3)(16,4) \left. \right \}

Total no. of ways of selecting two nos. = n(r) = 16 

product will be less than 16 is 

\left \{ \right. (1,1)(1,2) (1,3) ( 1,4)\\\\(4,1)(4,2)(4,3)(9,1) \left. \right \}

no. of getting product less than 16 = n(E) = 8 

probability of getting product less than 16 = P_1 = \frac{n (E)}{n(T)} =8/16 = 1/2

Posted by

Ravindra Pindel

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