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(a) Out of 0.1 molal aqueous solution of glucose and 0.1 molal aqueous          solution of KCl, which one will have higher boiling point and why ?

(b) Predict whether van’t Hoff factor,(i) is less than one or greater than one in the following :

(i) CH_{3}COOH dissolved in water

(ii) CH_{3}COOH dissolved in benzene

 

 

 

 
 
 
 
 

Answers (1)

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(a) 0.1 molal aq. solution of KCl shows higher boiling point because its 1 mole dissociates into 2 moles of ions.

             \underset{1}{KCl}\rightarrow \underset{2moles}{K^{+}+Cl^{-}}

      whereas Glucose remains as such without any dissociation.

(b)

(i) i> 1                  (ii) i< 1

Posted by

Sumit Saini

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