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A particle is moving with constant acceleration from A to B in a straight line AB. If u and v are the velocities at A and B respectively then its velocity at the midpoint C will be

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If the length of AB =s, then mispoint of AB is at s/2 

The velocity of the particle changes from u to v when it moves through the distance s

\\a=\frac{v^2-u^2}{2s}..(1)

Velocity at midpoint is 

\\v_c^2=u^2+\frac{2as}{2}....(2)

Substituting (1) in (2) we get

\\v_c^2=\frac{v^2+u^2}{2}\\v_c=\sqrt{\frac{v^2+u^2}{2}}

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Safeer PP

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