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  • A person travelling in a circular track of radius 100m,with tangential acceleration 2ms^-2. His angular acceleration is

A person travelling in a circular track of radius 100m,with tangential acceleration 2ms^-2. His angular acceleration is

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Given:

The radius of circular track =r= 100 m

Linear Acceleration ( tangential acceleration=a_t ) is 2 m/s².

To find-

Angular acceleration of the object=\alpha

so using

a_t=r \alpha

we get

\alpha= \frac{a_t}{r}=\frac{2}{100}=0.02 \ rad/(sec)^2

Posted by

avinash.dongre

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