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  • A ray PQ incident on the refracting face BA is refracted in the prism BAC as shown in the figure and emerges from the other refracting face AC as RS such that If the angl

A ray PQ incident on the refracting face BA is refracted in the prism BAC as shown in the figure and emerges from the other refracting face AC as RS such that AQ=AR. If the angle of prism A=60^{o} and refractive index of material of prism is \sqrt{3}, calculate angle \theta.

 

 
 
 
 
 

Answers (1)

QR\parallel BC

\therefore \theta =\delta _{m} ( angle of minimum deviation)

m=\frac{\sin (\frac{A+\delta _{m}}{2})}{\sin (\frac{A}{2})}

where m is the refractive index

\sin \left ( \frac{60+\delta _{m}}{2} \right )=\sin 30\times \sqrt{3}

                                  =\frac{\sqrt{3}}{2}

\Rightarrow \frac{60+\delta _{m}}{2}=60

\theta =\delta _{m}=60^{o}

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Safeer PP

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