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  • A solid of density 5000 kg m to the power -3 weighs 0.5 kg f in air.it is completely immersed in water of density 1000 kg m to the power of -3.calculate the apparent weigh of the solid in water?

A solid of density 5000 kg m to the power -3 weighs 0.5 kg f in air.it is completely immersed in water of density 1000 kg m to the power of -3.calculate the apparent weigh of the solid in water?

Answers (1)

\text{volume of the solid}=\frac{mass}{density}=\frac{0.5}{5000}=10^{-4}m^3

\\\text{mass of the water displaced}=V_{solid}\times\rho_{water}=10^{-4}\times10^{3}=0.1Kg

Apparent weight = (0.5-0.1)KgF

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Safeer PP

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