(a) Write the mathematical expression for Joule's law of heating.
(b) Compute the heat generated while transferring 96000 coulomb of charge in two hours through a potential difference of .
(a) Mathematical expression for Joule's law of heating is
H = I2Rt
(b) Heat generated while transferring 96000 coulomb of charge in two hours through a potential difference of is
H = V.I.t = V.Q
Given : V = 40 volts , Q = 96000 C
Therefore, H = 40 V × 96000 C = 3.84 × 106 J