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  • A(5, 1); B(1, 5) and C(–3, –1) are the vertices of ABC. Find the length of the median AD.    n

A(5, 1); B(1, 5) and C(–3, –1) are the vertices of \DeltaABC. Find the length of the median AD. 

 

 

 
 
 
 
 

Answers (1)

Given,A(5, 1); B(1, 5) and C(–3, –1) are the vertices of

\DeltaABC.

 coordinate of D : D is the midpoint of BC 

D = \left ( \frac{1+ (-3)}{2} , \frac{5 +( -1) }{2}\right )

Coordinate of D = (-1,2) 

length of AD = 

= \sqrt { ( y_2 - y_1 )^2 + (x_2 - x_1 )^2} \\\\ = \sqrt { ( 1-2 )^2 + ( 5- ( -1))^2}\\\\ \sqrt {( -1 )^2 + 6 ^2} \\\\ lenght \: \: of \: \: AD = \sqrt {37} \\\\

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Safeer PP

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