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  • An object is placed at a distance of 60 cm from a concave lens of focal length 30 cm. (i) Use lens formula to find the distance of the image from the lens. (ii) List four characteristics of the image (nature, position, size, erect/i

An object is placed at a distance of 60 cm from a concave lens of focal length 30 cm.

(i) Use lens formula to find the distance of the image from the lens.

(ii) List four characteristics of the image (nature, position, size, erect/inverted) formed by the lens in this case.

(ii) Draw ray diagram to justify your answer of part (ii).

 

 

 

 
 
 
 
 

Answers (1)

u = -60 cm

f = -30 cm

(i)      \frac{1}{f}=\frac{1}{v}-\frac{1}{u}

        \frac{1}{-30}=\frac{1}{v}-\left ( \frac{1}{-60} \right )

        \frac{1}{-30}-\frac{1}{60}=\frac{1}{v}

        \frac{-2-1}{60}=\frac{1}{v}

So, distance of image from lens = 20 cm

(ii) Nature \rightarrow Virtual

      Erect / Inverted \rightarrow Erect 

       Position \rightarrow Image will be formed b/w F_{1} and O

Now,         =\frac{v}{u}

                =\frac{-20}{-60}=0.33

        Size \rightarrow Diminished

(iii)

        `

 

 

 

Posted by

Sumit Saini

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