An object is placed in front of a convex mirror of focal length 15 cm. It produces an image that is half the size of the object. Find (a) position of the object, (b) nature of the image, and (c) draw the ray diagram of image formation.

 

Answers (1)

Given magnification=0.5

Therefore

v=0.5u

a)

\\\frac{1}{f}=\frac{1}{v}+\frac{1}{u}\\\\\frac{1}{15}=\frac{1}{-0.5u}+\frac{1}{u}\\u=-15cm

b) 

Nature of image: virtual, erect and diminished

c)

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