# An object near the surface of the earth with a weight of 50N is accelerated vertically upwards with a acceleration of 4m/s^2 with a rope of negligible weight tied to it. What is the force exerted by the rope on the object?

Given, weight of the object=50 N

so from here we can find the mass of the object, $50N=mg\Rightarrow m=\frac{50}{g}=\frac{50}{10}=5kg$

Now the body is accelerating in the upward direction and here the force exerted by the rope on the object will be in the upward direction and the weight of the body will be in the downward direction.

so the net force acting on the object, $F_{net}=T-mg$

From newton's second law we can write, $\sum F_{net}=ma$

$T-mg=ma\Rightarrow T=mg+ma=m(g+a)=5(10+4)=70N$

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