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Based on dot product of vectors: Prove that(A+2B). (2A-3B) =2A^2+AB cosÂ¢ -6B^2.

Answers (1)

A.A=A²

Similarly

B.B=B²

A.B=AB cos x where x is the angle between A and B

(A+2B). (2A-3B)=2A²-AB cos x -6B²

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