Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Calculate the amount of heat required to change 10 g of ice at minus 20 degree Celcius to water at 40degree Celsius. Take specific heat capacity of ice = 2.1 j/g/^0c, specific latent heat of ice =336 j/g & specific heat capacity of water =4.2 j/g/^0c

Calculate the amount of heat required to change 10 g of ice at minus 20 degree Celcius to water at 40degree Celsius. Take specific heat capacity of ice = 2.1 j/g/^0c, specific latent heat of ice =336 j/g & specific heat capacity of water =4.2 j/g/^0c

Answers (1)

Amount of heat required to change ice at -20 degree to 0-degree celsius.  
           = mass x specific heat * (T2-T1) = 10 gm x 2.1 J/gm/°C x (0°C - (-20° C)) 
                           = 420 Joules
     
To convert ice to water at a constant temperature 0C, energy required :                           

 = Latent Heat x mass =3360 J

Amount of heat required to change water a at 0 degree to 40 degree celsius: 
           = 10 gm x 4.2 J/gm/°C x (40°C - 0° C) 
               = 1680 Joules

Total heat needed = 420 J + 3360 J + 1680 J 
                    = 5, 460 J   

Posted by

Safeer PP

View full answer

Similar Questions

Latest Question