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Calculate the equivalent maas of kmno4 in the acidic medium​

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In acidic medium

MnO4- + 8H+ + 5e = Mn2+ + 4H2O

from this reaction we can deduce that Mn7+ reduced to Mn2+ so “ n factor” for this reaction is 5

Eq.wt = molecular weight / n factor

So for KMnO4 molecular weight is 158.g

So Eq.wt = 158/5 = 31.6 g per equivalent.

Posted by

sudhir.kumar

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