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  • Calculate the freezing point of a solution containing 60 g of glucose (Molar mass = 180 g mol-1 ) in 250 g of water. (Kf of water = 1·86 K kg mol-1)   <div style="float:left; width

Calculate the freezing point of a solution containing 60 g of glucose (Molar mass = 180 g mol-1 ) in 250 g of water. (Kf of water = 1·86 K kg mol-1)

 

 

 

 
 
 
 
 

Answers (1)

T_{f}=?

Weight of glucose = 60g

Weight of water = 250g

Kf of water = 1·86 K kg mol-1

Molar mass = 180 g mol-1

\Delta T_{f}=K_{f}\times m

\Delta T_{f}=1.86\times \frac{60}{180}\times \frac{1000}{250}=2.48K

\Delta T_{f}=T^{\circ}_{f}-T_{f}

T_{f}=T^{\circ}_{f}-\Delta T_{f}

T_{f}=273.15-2.48=270.67K

Posted by

Sumit Saini

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