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  • Calculate the freezing point of an aqueous solution containing 10.5 g of Magnesium bromide in 200 g of water, assuming complete dissociation of Magnesium bromide. (Molar mass of Magnesium bromide = 184 g mol –1, Kf

Calculate the freezing point of an aqueous solution containing 10.5 g of Magnesium bromide in 200 g of water, assuming complete dissociation of Magnesium bromide.

(Molar mass of Magnesium bromide = 184 g mol –1, Kf for water = 1.86 K kg mol –1).

 

 

 

 
 
 
 
 

Answers (1)

T_f = ?

MgBr_2\rightarrow Mg^{2+} + 2Br^{-}

i = 3

\Delta T_f = i\times K_f\times m

            =\frac{3\times 1.86\times 10.5\times 1000}{184\times 200}

            =1.59

\Delta T_f = T^o_f- T_f

1.59=173.15 - T_f

T_f = 173.15 - 1.59

       = 271.56 K

Posted by

Sumit Saini

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