Calculate the mass of ascorbic acid (Molar mass = 176 g mol-1) to be dissolved in 75 g of acetic acid, to lower its freezing point by x
Mass of acetic acid, w1= 75 g Molar mass of ascorbic acid (C6?H8?O6?),
M2=6×12+8×1+6×16 = 176gmol−1
Lowering of melting point, ΔTf? =1.5K
We know that:
ΔTb? =? Kb?×1000×w2??/(M2?×w1)
w2 ? =ΔTb?×M2?×w1??/ (Kb?×1000)
w2?=5.08g
Hence, 5.08 g of ascorbic acid is needed to be dissolved.