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Calculate the orbital period of the electron in the first excited, state of Hydrogen atom.

Answers (1)

S Safeer PP

The radius of the orbit

$r_n=\frac{0.53n^2A^{\circ}}{z}$

Velocity

$v_n=\frac{2.2\times10^6z}{n}$

Orbital period

$T=\frac{2\pi r_n}{v}=\frac{2\pi \times0.53n^3\times10^{-10}}{2.2\times10^6 z^2}$

The electron in the first excited state that is $n=2$ and $z=1$

$T=\frac{2\pi\times0.53\times8\times10^{-10}}{2.2\times10^6}=1.2\times10^{-15}s$

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