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Conductivity of 2\times 10^{^{-3}}M methanoic acid is 8\times 10^{-5}S\; cm^{-1}. Calculate its molar conductivity and degree of dissociation if   \wedge ^{\circ}m for methanoic acid is 404\; S\; cm^{2}\; mol^{-1}

 

 

Answers (1)
S safeer

\Lambdam = k x 1000/ M = 8 x 10-5 x 1000 / 2 x 10-3 = 40 Scm2mol-1

α= \Lambdam / \Lambdamo  = 40/ 404 = 0.099

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