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  • Derive an expression for velocity of a projectile at any instant of time

Derive an expression for velocity of a projectile at any instant of time

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Projectile Projected at angle Ï´

  • Initial Velocity-  U

           Horizontal component = U_{x} = Ucos\theta

           Vertical component = U_{y} = Usin\theta

  • Final velocity = V 

           Horizontal component = V_{x} = Ucos\theta

           Vertical component = V_{y} = Usin\theta - g.t

velocity at any time t is given as

\vec{V}=(U \cos \theta) \vec{i}+(U \sin \theta-g t)\vec{j}

So, its magnitude  is given as

                        V = \sqrt{V^{2}_{x} +V^{2}_{y}}

Posted by

avinash.dongre

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