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  • Draw a triangle with sides 5cm, 6cm and 7cm . Then draw another triangle whose sides are 4/5 of the corresponding sides of first triangle       

Draw a triangle with sides 5cm, 6cm and 7cm . Then draw another triangle whose sides are 4/5 of the corresponding sides of first triangle 

 

 

 

 
 
 
 
 

Answers (1)

AB = 6cm 

BC = 7 cm 

AC = 5 cm 

Steps for construction 

1) Draw BC = 7cm 

2) mark an arc of 6cm from point B 

3) mark another arc of 5cm from point C 

4) Name the point of intersection as A 

5) Join AB and AC 

6) \Delta ABC is formed 

6) Now draw a ray BX making an acute angle with BC 

7) Take scale factor 4/5 (<1) 

8) marks 5 points on BX (B_1 , B_2 ,B_3 ,B_4 ,B_5 )

 such that BB_1 =B_1 B_2 =B_3B_4 = B_4 B_5

9) join \: \: B_5 C

10 ) Join join \: \: B_4 C ' || B_5 C such that C' intersects BC 

11) Now draw join \: \: C 'A' || CA such that A' intersects AB 

12) \Delta A'BC' is formed 

 which is 4/5 \Delta ABC

Posted by

Ravindra Pindel

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