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  • Equation to the straight line cutting off an intercept 2 from the negative direction of the axis of y and inclined at 30 degree to the positive direction of x is

Equation to the straight line cutting off an intercept 2 from the negative direction of the axis of y and inclined at 30 degree to the positive direction of x is

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Solution: Let the equation of a straight  line is \ y =mx+c

Here ,\ m= an 30^circ=1/sqrt3;and;c=-2

Hence , the required equation is \ y=(1/sqrt3)x-2

\ sqrt3y-x+2sqrt3=0

Posted by

Deependra Verma

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