Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Estimate the ratio of the wavelengths associated with the electron orbiting around the nucleus in the first and second excited states of hydrogen atom.

Estimate the ratio of the wavelengths associated with the electron orbiting around the nucleus in the first and second excited states of hydrogen atom.

 

 
 
 
 
 

Answers (1)

The wavelength can find by using De-Broglie wavelength equation,

for electron, the first excited n=2.

By de-broglie's equation, n\lambda =2\pi r _{n}

where, r _{n} is the radius of second orbit,

r _{n}=n^{2}\left ( \frac{h^{2}\epsilon _{0}}{\pi m_{e}^{2}} \right )

      =n^{2}\times 0.527\; A^{\circ}

      =2.11\; A^{\circ}

Therefore, 2\times \lambda =2\times 3.14\times 2.11

                    \lambda =6.625\; A^{\circ}

For second excited state, n=3

            So, n\lambda =2\pi r_{n}

                    r_{n}=n^{2}\times 0.529\; A^{\circ}

                           =9\times 0.529\; A^{\circ}=4.761\; A^{\circ}

Therefore, 3\times \lambda =2\times 3.14\times 4.761

                        \lambda =\frac{29.899}{3}=9.966\; A^{\circ}

    Ratio,               =\frac{6.625}{9.966}

                            =0.66

ratio of the wave lengths is 0.66

Posted by

Safeer PP

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Central Sector Scheme of Scholarship 2025 applications open on scholarships.gov.in
anam-khan

CBSE Board 2025: Class 10th, 12th supplementary date sheet out; exams from July 15
anam-khan

CBSE issues final reminder to schools for supplementary exam LOC submission; submit by today without late fee

Latest Question