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Find integral zeroes of 2x^3+5x^2-5x-2

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2x^3+5x^2-5x-2
Rightarrow 2x^3-2x^2+7x^2-7x+2x-2
Rightarrow 2x^2(x-1)+7x(x-1)+2(x-1)
Rightarrow (2x^2+7x+2)(x-1)
The factors we get is (2x^2+7x+2) , and , (x-1)
One zero of the polynomial is,x-1=0Rightarrow x=1, , (integer)
On solving the other polynomial,(2x^2+7x+2)=0Rightarrow x=frac(-7pm sqrt33)4,Which is an irrational number
Hence the internal zero of the polynomial is only one eg.,x=1

Posted by

Deependra Verma

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