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#### find the coordinates of the centre of the circle which bisects the circumferences of the circles x^2+y^2=1, x^2+y^2+2x?3=0 and x^2+y^2+2y?3=0.

$x^2+y^2=1...(i)\\*x^2+y^2+2x-3=0...(ii)\\*x^2+y^2+2y-3=0....(iii)\\*using\;.....(i)\;and\;.....(ii)\\*\Rightarrow 1+2x-3=0\Rightarrow x=1\\*Now,\;using\;...(i)\; and\;...(iii)\\*\Rightarrow 1+3y-3=0\Rightarrow y=1\\*\therefore center \;of\;the\;such\;circle\;is\;(1,1)\\*$