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  • Find the frequency of light which ejects electrons from a metal surface, fully stopped by a retarding potential of . If photoelectric emission begins in this metal a

Find the frequency of light which ejects electrons from a metal surface, fully stopped by a retarding potential of 3.3\; V. If photoelectric emission begins in this metal at a frequency of 8\times 10^{14}Hz, calculate the work function (in eV) for this metal.

 

 

 

 
 
 
 
 

Answers (1)

Work function 

        \phi _{0}=h\nu _{0}

given. \nu _{0}=8\times 10^{4}Hz

            \phi _{0}=\frac{6.6\times 10^{-34}\times 8\times 10^{14}}{1.6\times 10^{-19}}eV

                    =3.3\; eV

Maximum kinetic energy 

                eV_{0}=h\nu -\phi _{0}

                 3.3 =h\nu -\phi _{0}

                    h\nu =6.6\; eV

                     \nu =\frac{6.6\times 1.6\times 10^{-19}}{6.6\times 10^{-34}}Hz

                         =1.6\times 10^{15}\; Hz       

Posted by

Safeer PP

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