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:Solution: we have the given line
L: 12x - 5y - 41 = 0 — (1 ) slope (m)= 5 /12
⇒ equation of the line passing through ( 2 ,1) and perpendicular to the given line
⇒ ( y -1 ) = -5 /12( x - 2)
⇒ 5x + 12y = 22 — (2)
Now , intersection of the line (1) and (2) is (-4 ,7/2)
let ( a,b) be the reflection point
Then ( a + 2) /2 = -4 and ( b +1 ) / 2 = 7/2
a = -10 And b = 6