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  • Find the value of a+b+c+d if product of first 10 natural numbers is written as 2^a . 3^b . 5^c .7^d

Find the value of a+b+c+d if product of first 10 natural numbers is written as 2^a . 3^b . 5^c .7^d

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  2^a*3^b*5^c*7^d=1*2*3*4*5*6*7*8*9*10 & \\ 2^a*3^b*5^c*7^d =1*2*3*2^2*5*2*3*7*2^3*3^2*2*5\\ 2^a*3^b*5^c*7^d=2^8*3^4*5^2*7^1

so a=8, b=4, c=2 and d=1
a+b+c+d=15

Posted by

avinash.dongre

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