Find the values of 3 tan^6 10 (degree) -27tan^4 10 (degree) +33 tan^2 10 (degree) =?

Answers (1)

Solution:   We have ,

                  3	an^610^circ-27	an^410^circ+33 	an^210^circ

             Let     t=	an 10^circ,	an 30^circ=frac1sqrt3Rightarrow frac3t-t^31-3t^2=frac1sqrt3

            Squaring  ,     3t^6-27t^4+33t^2=1

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