# Find the vertex, focus, axis, directrix and lotus â€“ rectum of the parabola y^2 = 8x.

$Given:Parabola=y^2=8x\\*Now\;by\;comparing\;with\;the\; actual\;parabola\;y^2=4ax\\*Then,\\*4a=8\\*\Rightarrow a=\frac{8}{4}=2\\*So,\;the\;vertex\;is\;(0,0)\\* The\;focus\;is\;(a,0)=(2,0)\\*The\;equation\;of\;the\;axis\; is\;y=0\\*The\;equation\;of\;the\;directrix\;is\;x=a\;i.e.,\; x=-2\\*The\;length\;of\;the\;latus\;rectum\;is\;4a=8\\*$

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