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Get Answers to all your Questions
For a 5% solution of urea (Molar mass = 60 g/mol), calculate the osmotic pressure at 300 K. [R = 0·0821 L atm K-1 mol-1]
Answers (1)
Given,
5% urea solution means 5g urea is present in 100ml of solution.
moles of urea present =weight given/Molecular weight of urea
=5g / 60gmol−1=112
Hence Concentration of urea = (moles of urea(n) /volume of solution ) ×1000
={(112)/100}∗1000
=1012
Hence Osmotic pressure =1×(10/20)×0.082×300 atm
=20.52atm
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