# How is the time period of a simple pendulum affected, if its length increase by four times?

The time period of a simple pendulum is given by

$T=2\pi \sqrt{\frac{l}{g}}$

So keeping g= constant

if we increase its length by four times

i.e $l'=4l$

So

$T'=2\pi \sqrt{\frac{l'}{g}}=2\pi \sqrt{\frac{4l}{g}}=2*(2\pi \sqrt{\frac{l}{g}})=2T$

i.e Its time period will increase by 2 times

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