How is the time period of a simple pendulum affected, if its length increase by four times?

Answers (1)

 The time period of a simple pendulum is given by 

T=2\pi \sqrt{\frac{l}{g}}

So keeping g= constant 

if we increase its length by four times

 

i.e l'=4l

So 

T'=2\pi \sqrt{\frac{l'}{g}}=2\pi \sqrt{\frac{4l}{g}}=2*(2\pi \sqrt{\frac{l}{g}})=2T

i.e Its time period will increase by 2 times

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