How much charge in terms of Faraday is required to reduce one mol of MnO_{4}^{-} to Mn^{2+} ?

 

Answers (1)

It goes from +7 to +2 oxidization state, hence the change of 5 electronic charges is seen in one molecule, hence 5F of charge is required to reduce one mol of MnO_{4}^{-} to Mn^{2+} 

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