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  • If 2+square root 5 i is a root of x^2-px+q=0 where p and q are real , then the order pair (p,q) is equal to.

If 2+square root 5 i is a root of x^2-px+q=0 where p and q are real , then the order pair (p,q) is equal to.

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Solution: We  have,    x^2-px+q=0

                 alpha =2+sqrt5i   ,   eta =2-sqrt5i

           p,q in R    Rightarrow  alpha +eta =p=4 and  alpha cdot eta =q=(2+sqrt5i)(2-sqrt5i)=9

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Deependra Verma

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